4x^2+32x-12=0

Solution for 4x^2+32x-12=0 equation:

4x^2+32x-12=0

a = 4; b = 32; c = -12;
Δ = b2-4ac
Δ = 322-4·4·(-12)
Δ = 1216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1216}=\sqrt{64*19}=\sqrt{64}*\sqrt{19}=8\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8\sqrt{19}}{2*4}=\frac{-32-8\sqrt{19}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8\sqrt{19}}{2*4}=\frac{-32+8\sqrt{19}}{8}
$